M24C04-F DNF5 I2C address

[MMici.1]

Dear All,

can someone, please, specify the meaning of the bit 1 as 'A8' in the I2C address of the M24C04-FMH6TG?

I can't find any explanation of this value.

 

Thank you

[Peter BENSCH]

The M24C04 contains 512 (2^9) bytes, which require 9 bits for addressing. Since an address byte only has 8 bits (A0...A7), the 9th bit (A8) must also be transferred, for which bit b1 in the device select code is used.

Does it answer your question?

Regards
/Peter

[MMici.1]

Of course, thanks :D.