I have Question about MCM_Clarke conversion.

[gkim.19]

Dear sir.

I am analyzing the FOC algorithm using motor control workbench 6.10.

During the analysis of the FOC algorithm, I do not understand the MCM_Clarke function part.

In the case of Clarke transformation I know, it is an algorithm that converts three axes into two axes. However, at mcm, it seems to convert two axes into two axes as shown below.

 alpha = a

 beta = -(2*b+a)/sqrt(3)

Maybe I can get some help?

[Gael A]

Hello gkim.19 (Community Member),

The answer relies on an additional equation : a + b + c = 0, which we use to remove any c value from our results to depend only on a and b values. This is why you might at first think MCM_Clarke converts two axes into two axes and not three axes into two axes.

Developing my point, we start with :

which gives :

We find the values given in MCM_Clarke function.

Hoping this will help,

Gaël A.

[gkim.19]

Thank you.

I thought about the above conversion for a long time.

But, I didn't think of going crazy with the rule of a+b+c=0 and substituting it for this formula.

Your a+b+c=0 core solved everything.

I'm much obliged to you for your help

Best regards,

Gaël A.