EMI FLASH

[666jack666]

Posted on November 09, 2005 at 10:40

EMI FLASH

[666jack666]

Posted on November 02, 2005 at 10:59

Hi. I've got evaluation board MB393B. I don't be able read CFI Query Identification String. I tried this:

GPIO_Config(GPIO2,0xF,GPIO_AF_PP);

EMI_Config(0, EMI_WAITSTATE(14)|EMI_ENABLE|EMI_SIZE_16);

*(u32*)0x6000000 = 0x00000098;

data = *(u32*)0x6000000; //Manufacturer Code

Can anybody help me? Thanks Jack

[tech9]

Posted on November 02, 2005 at 11:52

Hi,

Making sure ALL of your pins are configured as GPIO_AF_PP (it is rather evident that the bus should be configured properly), so try this; works fine with my board...

GPIO_Config(GPIO2, 0x0001 , GPIO_AF_PP); // Bank0 CS (Flash)

GPIO_Config(GPIO2, 0x0002 , GPIO_AF_PP); // Bank1 CS (SRAM)

GPIO_Config(GPIO2, 0x0004 , GPIO_AF_PP);

GPIO_Config(GPIO2, 0x0010 , GPIO_AF_PP); // Addr20-23

GPIO_Config(GPIO2, 0x0020 , GPIO_AF_PP);

GPIO_Config(GPIO2, 0x0040 , GPIO_AF_PP);

GPIO_Config(GPIO2, 0x0080 , GPIO_AF_PP);

//configure the EMI so /CSO is pointing the flash, 16 bits large, 15 WS

EMI_Config(0, EMI_ENABLE | EMI_WAITSTATE(15) | EMI_SIZE_16);

//the board has a ST M28W320CB chip on it...

//read electronic signature, for manuf and device

*(u8*) 0x60000000=0x90;

u32 EMIData=*(u32*)0x60000000; //should be 00 02: manuf code

*(u8*) 0x60000000=0x90;

EMIData=*(u32*)0x60000002; //should be 88 BB: device code-Bottom block

Best regards,

tech

[666jack666]

Posted on November 03, 2005 at 08:39

Thank you, tech.

It works, but I don't know why is the address 60000002, why isn't there 60000001 (I found it in data sheet.)? It works with 2, but I don't know why. EMIData=*(u32*)0x60000002; //should be 88 BB: device code-Bottom block

Can You give me an example with writing and reading something to Flash?

I tried:

Vpp_On(); //Vpp high

*(u8*)(0x60000000)=0x0040; //write command

*(u32*)(0x60000EEE)=0x1234; //write 1234

*(u8*) 0x60000000=0x00FF; //read command

data=*(u32*)0x60000EEE; //should be 1234

Thank You Jack.

[666jack666]

Posted on November 04, 2005 at 04:08

Hi, it's pointer to 16-bit variable, so address is 0, 2, 4, ... I think. Jack.

[tech9]

Posted on November 04, 2005 at 10:57

You tought right. 16 bit means even addressing...

Example to read:

u16 function_to_read(u32 add)

*(u8*)0x60000000=0xFF;

return *(u16*)add;

and to write:

u8 program(u32 add, u16 data)

*(u8*)0x60000000=0x40;

*(u16*)add=data;

You should read the datasheet on the M28W320CB, lots of good things to find... particularly about errors from the status register.

Note: you won't be able to ``see`` the data you wrote in the debugger, just the status register(sometimes), because obviously the debugger is not sending the appropriate command to read the flash. Reading the flash back with a temp variable is your best option. Also, write a routine to read the status register, you'll find millions of use for it (waiting for a write completion, checking errors, erase status...)

Have fun!

Best regards,

Jp

[666jack666]

Posted on November 09, 2005 at 03:45

Hi. Thank you. I found out that I have set bits in Protection Register Lock (0x0006). Is it impossible clear them? Jack.

[tech9]

Posted on November 09, 2005 at 10:40

Check out the M28W320 datasheet, everything you need is in there; block unlock is at p. 14

I attached the document for your reference. (.pdf format)

Regards,

Tech

________________

Attachments :

m28w320cb.pdf : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I1Oz&d=%2Fa%2F0X0000000bmY%2FBvX8UrgVchKY6.i48pGGsdoN0w2QMX621EFCxJ_p20g&asPdf=false