Problem on Interrupt (VIC0 and VIC1)

[acorradini9]

Posted on September 19, 2007 at 07:53

Problem on Interrupt (VIC0 and VIC1)

[lodedeschepper]

Posted on May 17, 2011 at 09:33

Hello,

My interrupts:

 

VIC0_VA4R = (u32)TIM0_IRQHandler; // for dma

 

VIC0_VA6R = (u32)TIM2_IRQHandler; // 2ms timer

 

VIC0_VA12R = (u32)DMA_IRQHandler;

 

VIC1_VA2R = (u32)UART2_IRQHandler;

 

VIC1_VA3R = (u32)I2C_IRQHandler;

 

VIC1_VA13R = (u32)EXT_IO_IRQHandler;

 

For testing I continiously read and write to an external EEPROM. After a certain time the processor resets. After the help on this forum, i modified my code with 2 default IRQ functions: (as suggested by JAL)

 

void Default0_IRQHandler( void ) __attribute ((interrupt(''IRQ'')));

 

void Default0_IRQHandler( void ){

 

spuriousInterruptCount0++;

 

VIC0_VAR = 0;

 

}

 

 

void Default1_IRQHandler( void ) __attribute ((interrupt(''IRQ'')));

 

void Default1_IRQHandler( void ){

 

spuriousInterruptCount1++;

 

VIC1_VAR = 0;

 

}

 

 

VIC0_DVAR = (u32)Default0_IRQHandler;

 

VIC1_DVAR = (u32)Default1_IRQHandler;

 

After a certain time, Default1_IRQHandler is entered and spuriousInterruptCount1 is incremented. After returning, the continious read/write to I2C didn't continue...

Then I modified the 2 default IRQ functions:

 

void Default0_IRQHandler( void ){

 

spuriousInterruptCount0++;

 

 

VIC0_VAR = 0;

 

VIC1_VAR = 0;

 

 

}

 

void Default1_IRQHandler( void ){

 

spuriousInterruptCount1++;

 

 

VIC0_VAR = 0;

 

VIC1_VAR = 0;

 

 

}

And up till now, it keeps on working!!!

Read/write tests to the EEPROM: 4120

spuriousInterruptCount1: 81

spuriousInterruptCount0: 0

I hope this solution is suitable for devellopers with simular problems.

Best Regards,

Louis XIV