problem with timer

[efeixas]

Posted on September 11, 2003 at 10:31

problem with timer

[efeixas]

Posted on August 30, 2003 at 15:11

I've tried to do an interrupt every 1ms using the output compare 1 of the timer b without succes.

I've attached my program but until now it does'nt work because after the first interrupt it re-enter autamaticaly in the interrupt without waiting the time put in timer. Could anyone say me how can i reset the interrupt?

Thanks

________________

Attachments :

prova.txt : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I0C9&d=%2Fa%2F0X0000000bV7%2F1V_gSoRp9oX1XxYS1uUuR5TpYC9ag6aEcSYMvbcmd5U&asPdf=false

[marco32]

Posted on September 01, 2003 at 05:57

You've forgotten to clear the interrupt flag.

You must read the OCF1 flag in the Status register.

Read the datasheet, chapter 'timer' for more details

Moppie

[efeixas]

Posted on September 02, 2003 at 16:56

Thanks, for your hepl, but it still don't work. I have already the same problem could you see the new program in order to say me if there is anithing wrong?

Thanks

Enric Feixas

________________

Attachments :

prova.txt : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I0C4&d=%2Fa%2F0X0000000bV4%2FrIntWekPn3ZIBVLvr5lqRs1._ufHUN_4joN63LxC1A8&asPdf=false

[sisto]

Posted on September 03, 2003 at 06:13

Hi Enric,

Try this code example.

It's a ''C'' code but You can convert it in assembler.

/* Definizione costanti */

#if(_freqOsc == 16 ) // < 16MHz >

#define _oneMilli 1000 // costante timer free-running per ottenere il millisecondo

#define _CC01 0b00001000 // divisore frequenza CPU (OSC/2) per il timer A o B a 1MHz

#endif

#if(_freqOsc == 8 ) // < 8MHz >

#define _oneMilli 1000 // costante timer free-running per ottenere il millisecondo

#define _CC01 0b00000000 // divisore frequenza CPU (OSC/2) per il timer A o B a 1MHz

#endif

/* Variabile WORD di supporto */

@tiny WORD Delay; // variabile per il ritardo di 1ms usata nell'interrupt timer

/* Inizializzazione TIMER ''A'' */

TACR1 = 0x40; /* abilito l'interrupt out Compare su TIMER ''A''*/

TACR2 = _CC01; /* divisione del clock per il conteggio; Fcpu/x = 1MHz*/

/* Timer intarrupt handler */

@interrupt void one_milli(void) /* ROUTINE DI INTERRUPT TIMER ''A'' o ''B'' */

{

if(ValBit(TASR,OCF1)) // ogni 1 millisecondo

{

Delay =(TAOC1HR<

Delay += _oneMilli; // somma di nuovo il valore per ottenere il millisecondo

TAOC1HR=(Delay>>8 ); // questa operazione effettua anche l'ack dell'interrupt

TAOC1LR=Delay;

// ...

// Your code

//

}

else TAOC2LR = 0x00;

[ Questo Messaggio è stato Modificato da: sixtus il 03-09-2003 09:45 ]

[marco32]

Posted on September 03, 2003 at 12:29

I've attached you're program.

First load the interrupt registers and then clear teh interrupt flag.

________________

Attachments :

prova2.txt : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I0BR&d=%2Fa%2F0X0000000bV1%2FVAFmZwwer8qvkzciokz4fMWFiJjJebfn7Bq1exR876s&asPdf=false

[efeixas]

Posted on September 03, 2003 at 19:23

Thanks for your help, but it still do'nt work, now I've a different problem, now it's too slowly, it spend 120ms to do the interrupt which I wanted to do in 1ms, could you look in the program what is wrong now?

Thanks

Enric Feixas

________________

Attachments :

prova2.txt : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I0Bv&d=%2Fa%2F0X0000000bV0%2FijjgziwC6.fMLM88JK1olReJbxslAPgTyzsS_2azUto&asPdf=false

[marco32]

Posted on September 04, 2003 at 12:45

Hello,

Look inside the attachment.

Good luck.

Read carefully the datasheets.

________________

Attachments :

prova2.asm : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I09V&d=%2Fa%2F0X0000000bV2%2F_JMPJOLCAJb0lcJneoWsnsO8SQClw83mfWNYp6j1PQI&asPdf=false

[efeixas]

Posted on September 06, 2003 at 20:55

Thanks to all of your help, I've solved teh problem! the answer is the program that you can see attached.

But now I've a new problem because I've started to do another timer with the output compare 2 of timer A, this not and interruption because I only want to put this output in 'ON' at the time I've put in the timer A (different from B). But after putting it in on I want to put it in OFF every time that the interrupt of timer B is activated but I could'nt!

Could you see in the program what is wrong?

Thanks

Enric Feixas

________________

Attachments :

Demo.asm : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I07f&d=%2Fa%2F0X0000000bV3%2Fg59r0.aMqOkaSOuK40i.3ouGvgeGonP.EN6mSbiDBQI&asPdf=false

[marco32]

Posted on September 08, 2003 at 06:13

Hello,

Great you solved the last problem.

You're next problem are in the intterupt vectors

Timer A and B has different interrupt vectors, so split up the intterupt

See the attachment

Succes.

[ This message was edited by: Moppie on 08-09-2003 09:44 ]

________________

Attachments :

Demo.asm : https://st--c.eu10.content.force.com/sfc/dist/version/download/?oid=00Db0000000YtG6&ids=0680X000006I0Bp&d=%2Fa%2F0X0000000bUx%2Fp38Aie.dXiP9.F7SRKxFtk06LZzf5K.bFCLHO2RSFvU&asPdf=false

[efeixas]

Posted on September 08, 2003 at 18:35

Thanks for your help, but it still continue with the same problem (after I put the led of output compare 2 in 'ON' I can't put it in 'OFF') , could you say me if there is anything which could be wrong?

Thanks.

Enric Feixas