Skip to main content
Visitor II
May 22, 2025
Solved

st25r3911b VHBR ISO 14443A

  • May 22, 2025
  • 1 reply
  • 798 views

st25r3911b in 14443A mode

TX: BITRATE_848

RX: BITRATE_1695

tx is successful,when  receive , switch B mode  , but  fail  :CRC error ,soft framing error and hard framing error

how can I solve this problem or Which registers still need to be modified?

    This topic has been closed for replies.
    Best answer by Ulysses HERNIOSUS

    Hi,

    ST25R3911B supports only VHBR for ISO14443B. Although modulation scheme of A VHBR and B VHBR are the same, however the frame format is different (A VHBR having parity bits and CRC_A, where as B VHBR having start and stop bits and CRC_B).

    I think you will not be able to succeed this way. Only if you would dive into transparent mode and let MCU do everything.

    BR, Ulysses

    1 reply

    Technical Moderator
    May 22, 2025

    Hi,

    ST25R3911B supports only VHBR for ISO14443B. Although modulation scheme of A VHBR and B VHBR are the same, however the frame format is different (A VHBR having parity bits and CRC_A, where as B VHBR having start and stop bits and CRC_B).

    I think you will not be able to succeed this way. Only if you would dive into transparent mode and let MCU do everything.

    BR, Ulysses

    memoAuthor
    Visitor II
    May 22, 2025

    I see,Thank you.

    Technical Moderator
    May 22, 2025

    Hi,

    to clarify this: VHBR is possible in B only. Tx in fc/8, fc/4, fc/2. Rx in fc/8 and fc/4. DS11793 rev7 is incorrect in this aspect.

    BR, Ulysses