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SnoZek
Associate III
August 3, 2023
Solved

ST25R3911B Field Strengh Ratio

  • August 3, 2023
  • 1 reply
  • 1266 views

Hello,

I'm working with ST25R3911B and in my application i want to control the field strengh.

I relied on the documentation at this chapter : 1.3.40 RFO normal level definition register page 80 in the Datasheet - ST25R3911B - High performance HF reader / NFC initiator with 1.4 W supporting VHBR and AAT

SnoZek_0-1691068341234.png

And, if i understand well if i write 0x00 in the 0x27 register it will enable all Ohms segments, it will make 510 ohms.

If i write 0x01 510-256=254 right ?

But when I test my application with a field detectorit it doesn't seem to react as expected. 

Am I doing something wrong ?

Best regards,

Yvan

This topic has been closed for replies.
Best answer by Ulysses HERNIOSUS

Hi Yvan,

the segments of the drivers are parallel. Thus you also need to apply calculation of parallel resistors, not series resistors (check e.g. https://en.wikipedia.org/wiki/Resistor). 

Regards, Ulysses

1 reply

Ulysses HERNIOSUS
Technical Moderator
August 4, 2023

Hi Yvan,

the segments of the drivers are parallel. Thus you also need to apply calculation of parallel resistors, not series resistors (check e.g. https://en.wikipedia.org/wiki/Resistor). 

Regards, Ulysses

SnoZek
SnoZekAuthor
Associate III
August 4, 2023

Hello Ulysses,

Thanks for help

If i understand well the value of the resistance depending on the register looks like this ? 

SnoZek_1-1691150468393.png

Regards,

Yvan

 

 

 

Ulysses HERNIOSUS
Technical Moderator
August 7, 2023

Correct.