HAL_I2C_Mem_Write with 24LC01B EEPROM

Hi there!

here i'm for ask another help. I use STM32G031 for write and read eeprom 24LC01B , and i work with

where Address = 0x01;

HAL_I2C_Mem_Write(hi2c, DevAddress, Address , I2C_MEMADD_SIZE_8BIT, &val, 1, 100);

so if i wrote 7 byte everythingh work perfect if i wrote 8 byte ti find the last byte in the position 0x00 in my eeprom why ?

if i change eeprom like 24lc256 and I2C_MEMADD_SIZE_16BIT

HAL_I2C_Mem_Write(hi2c, DevAddress, Address , I2C_MEMADD_SIZE_16BIT, &val, 1, 100); everythingh work perfect

please can you help me ?

Thanks

Sergiio

This topic has been closed for replies.

Best answer by Andrew Neil

@SGian.1 wrote:
where Address = 0x01;

Don't you need to start at Address = 0x00 ?

If you write 8 bytes from Address 0x01, you'll go over a "page" boundary?

Super User

@SGian.1 wrote:
where Address = 0x01;

Don't you need to start at Address = 0x00 ?

If you write 8 bytes from Address 0x01, you'll go over a "page" boundary?

Visitor II

My God i diden't take care of it.

Sorry

Thank you soo much

Sergio

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