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Graduate II
June 3, 2021
Solved

How does the HAL/LL function LL_GPIO_SetPinMode() work?

  • June 3, 2021
  • 1 reply
  • 2082 views

Ok, I scratched my head long enough and now my hope lies with the ST Community. =)

I would like to understand how this code in the header file stm32f1xx_ll_gpio.h works. In particular, what does (Pin >> 24) do? I suspect that the code sets two registers: GPIOx_BSRR and GPIOx_CRL. Here:

Pin = LL_GPIO_PIN_5

GPIOx = GPIOC

Thank you.

__STATIC_INLINE void LL_GPIO_SetPinMode(GPIO_TypeDef *GPIOx, uint32_t Pin, uint32_t Mode)

{

 register uint32_t *pReg = (uint32_t *)((uint32_t)(&GPIOx->CRL) + (Pin >> 24));

 MODIFY_REG(*pReg, ((GPIO_CRL_CNF0 | GPIO_CRL_MODE0) << (POSITION_VAL(Pin) * 4U)),

Mode << (POSITION_VAL(Pin) * 4U)));

}

    This topic has been closed for replies.
    Best answer by TDK

    The 26th bit is 1 for pins 8 and higher which makes the code set pReg to point to GPIOx->CRH rather than GPIOx->CRL.

    #define LL_GPIO_PIN_0 ((GPIO_BSRR_BS0 << GPIO_PIN_MASK_POS) | 0x00000001U) /*!< Select pin 0 */
    #define LL_GPIO_PIN_1 ((GPIO_BSRR_BS1 << GPIO_PIN_MASK_POS) | 0x00000002U) /*!< Select pin 1 */
    #define LL_GPIO_PIN_2 ((GPIO_BSRR_BS2 << GPIO_PIN_MASK_POS) | 0x00000004U) /*!< Select pin 2 */
    #define LL_GPIO_PIN_3 ((GPIO_BSRR_BS3 << GPIO_PIN_MASK_POS) | 0x00000008U) /*!< Select pin 3 */
    #define LL_GPIO_PIN_4 ((GPIO_BSRR_BS4 << GPIO_PIN_MASK_POS) | 0x00000010U) /*!< Select pin 4 */
    #define LL_GPIO_PIN_5 ((GPIO_BSRR_BS5 << GPIO_PIN_MASK_POS) | 0x00000020U) /*!< Select pin 5 */
    #define LL_GPIO_PIN_6 ((GPIO_BSRR_BS6 << GPIO_PIN_MASK_POS) | 0x00000040U) /*!< Select pin 6 */
    #define LL_GPIO_PIN_7 ((GPIO_BSRR_BS7 << GPIO_PIN_MASK_POS) | 0x00000080U) /*!< Select pin 7 */
    #define LL_GPIO_PIN_8 ((GPIO_BSRR_BS8 << GPIO_PIN_MASK_POS) | 0x04000001U) /*!< Select pin 8 */
    #define LL_GPIO_PIN_9 ((GPIO_BSRR_BS9 << GPIO_PIN_MASK_POS) | 0x04000002U) /*!< Select pin 9 */
    #define LL_GPIO_PIN_10 ((GPIO_BSRR_BS10 << GPIO_PIN_MASK_POS) | 0x04000004U) /*!< Select pin 10 */
    #define LL_GPIO_PIN_11 ((GPIO_BSRR_BS11 << GPIO_PIN_MASK_POS) | 0x04000008U) /*!< Select pin 11 */
    #define LL_GPIO_PIN_12 ((GPIO_BSRR_BS12 << GPIO_PIN_MASK_POS) | 0x04000010U) /*!< Select pin 12 */
    #define LL_GPIO_PIN_13 ((GPIO_BSRR_BS13 << GPIO_PIN_MASK_POS) | 0x04000020U) /*!< Select pin 13 */
    #define LL_GPIO_PIN_14 ((GPIO_BSRR_BS14 << GPIO_PIN_MASK_POS) | 0x04000040U) /*!< Select pin 14 */
    #define LL_GPIO_PIN_15 ((GPIO_BSRR_BS15 << GPIO_PIN_MASK_POS) | 0x04000080U) /*!< Select pin 15 */

    1 reply

    TDKAnswer
    Super User
    June 3, 2021

    The 26th bit is 1 for pins 8 and higher which makes the code set pReg to point to GPIOx->CRH rather than GPIOx->CRL.

    #define LL_GPIO_PIN_0 ((GPIO_BSRR_BS0 << GPIO_PIN_MASK_POS) | 0x00000001U) /*!< Select pin 0 */
    #define LL_GPIO_PIN_1 ((GPIO_BSRR_BS1 << GPIO_PIN_MASK_POS) | 0x00000002U) /*!< Select pin 1 */
    #define LL_GPIO_PIN_2 ((GPIO_BSRR_BS2 << GPIO_PIN_MASK_POS) | 0x00000004U) /*!< Select pin 2 */
    #define LL_GPIO_PIN_3 ((GPIO_BSRR_BS3 << GPIO_PIN_MASK_POS) | 0x00000008U) /*!< Select pin 3 */
    #define LL_GPIO_PIN_4 ((GPIO_BSRR_BS4 << GPIO_PIN_MASK_POS) | 0x00000010U) /*!< Select pin 4 */
    #define LL_GPIO_PIN_5 ((GPIO_BSRR_BS5 << GPIO_PIN_MASK_POS) | 0x00000020U) /*!< Select pin 5 */
    #define LL_GPIO_PIN_6 ((GPIO_BSRR_BS6 << GPIO_PIN_MASK_POS) | 0x00000040U) /*!< Select pin 6 */
    #define LL_GPIO_PIN_7 ((GPIO_BSRR_BS7 << GPIO_PIN_MASK_POS) | 0x00000080U) /*!< Select pin 7 */
    #define LL_GPIO_PIN_8 ((GPIO_BSRR_BS8 << GPIO_PIN_MASK_POS) | 0x04000001U) /*!< Select pin 8 */
    #define LL_GPIO_PIN_9 ((GPIO_BSRR_BS9 << GPIO_PIN_MASK_POS) | 0x04000002U) /*!< Select pin 9 */
    #define LL_GPIO_PIN_10 ((GPIO_BSRR_BS10 << GPIO_PIN_MASK_POS) | 0x04000004U) /*!< Select pin 10 */
    #define LL_GPIO_PIN_11 ((GPIO_BSRR_BS11 << GPIO_PIN_MASK_POS) | 0x04000008U) /*!< Select pin 11 */
    #define LL_GPIO_PIN_12 ((GPIO_BSRR_BS12 << GPIO_PIN_MASK_POS) | 0x04000010U) /*!< Select pin 12 */
    #define LL_GPIO_PIN_13 ((GPIO_BSRR_BS13 << GPIO_PIN_MASK_POS) | 0x04000020U) /*!< Select pin 13 */
    #define LL_GPIO_PIN_14 ((GPIO_BSRR_BS14 << GPIO_PIN_MASK_POS) | 0x04000040U) /*!< Select pin 14 */
    #define LL_GPIO_PIN_15 ((GPIO_BSRR_BS15 << GPIO_PIN_MASK_POS) | 0x04000080U) /*!< Select pin 15 */

    Kmax18Author
    Graduate II
    June 3, 2021
    Thank you for your response. Would it not be easier to point to point to GPIOx->CRH instead of manipulating the register address? What is the motivation for the algorithm?
    Super User
    June 3, 2021
    Pointing to CRH doesnt help if half the pins need CRL and the other half need CRH. There are other ways to implement it but this one seems okay if a bit obfuscated.
    Of note, doing shifts to implement this rather than conditional if statements allows instructions to be streamlined, not that it matters much for the M0 core.