Built in bootloader jump to address

[psusi]

AN2606 indicates that I should be able to activate the built in boot loader by jumping to the correct address in ROM, but I can't work out what that address is for the STM32U535CB.

 

[TDK]

Jump to the address specified by the vector table at 0x0BF90000.

How to jump to system bootloader from application ... - STMicroelectronics Community

 

[STOnizuka09]

 

Hello @psusi ,

The relevant information in AN2606 is provided in Table 214, “STM32U535xx/545xx configuration in System Memory boot mode,” which indicates that the System Memory bootloader base address for the STM32U535 is 0x0BF90000. This same address applies to the entire STM32U5 family.

Note that when transferring execution to the System Memory bootloader, it is recommended to:

- Disable all interrupts.
- Clear all pending interrupts.
- Stop SysTick.
- De-initialize peripherals used by the application.
- Restore the clock configuration to a reset-like state, including disabling any PLLs enabled by the application.
- Load the MSP from the first entry of the System Memory vector table.
- Jump to the reset handler from the second entry of the System Memory vector table.

Best regards.

[TDK]

@STOnizuka09 Something is off with this reply. The addresses in Table 3 do not match what is done here:

https://community.st.com/t5/stm32-mcus/how-to-jump-to-system-bootloader-from-application-code-on-stm32/ta-p/49424

Literally none of them match. The OP asked for an address to jump to. Which is correct?

[MM..1]

Right is 0x0BF90000, but this isnt jump address! Here start VTOR table then first u32 is MSP and second stored value on 0x0BF90004 is address to jump...