Clarification in datasheet of VNL5300S5TR-E

[Bitesh]

I'm planning to use 24V 0.5A Motor in application. It will be controlled from MCU which is taking 3.3V input and it's GPIO will give 3.3V when output pin is logic high. I'm thinking to interface the Motor to MCU via driver VNL5300S5TR-E.

Now I have doubts in this driver VNL5300S5TR-E.

1. This VNL5300S5TR-E IC is running on 3.5V to 5V. so I'm giving Vcc pin to 5V but input pin of this IC will be driven from MCU which will make input pin of IC to 3.3V.

so 3.3V voltage is sufficient to turn on the Internal MOSFET ?

2.There is a truth table 14 in the datasheet which says that STATUS Pin will get low for condition Output voltage < VOL. What is this condition, can you explain in detail.

3.Also what is this Openload detection table 10. in the datasheet. Can you tell more about this.

Regards,

Bitesh

[Peter BENSCH]

Welcome, @Bitesh​, to the community!

1. VNL5300S5-E is not only a MOSFET, but also contains a complete MOSFET driver including the diagnostic function in addition to protection functions. The pin INPUT can therefore be driven in the entire range of Vsupply (3.5-5.5V) with the levels mentioned in table 9: VIL ≤0.9V, VIH ≥2.1V, which means that INPUT can be driven with a 3.3V MCU, even with TTL compatible levels.
2. Table 14, Output voltage < VOL means: STATUS = active (L) when INPUT = L and no load connected or interrupted.
3. Table 10, VOL: this is the limit below which a missing load (open/disconnected, interrupted) can be detected if the INPUT is simultaneously switched active inactive (L).

Does it answer your question?

Regards

/Peter

[Bitesh]

Hi Peter,

Thanks for your response. Point 1 is clear to me now. but I still have confusion in Point 3.

Do you mean Output Voltage as Voltage on the Drain of MOSFET ?

If yes then I expect that when Input Voltage is LOW and No Load is connected then the Drain of MOSFET will be floating and reading some random noise. In this case Drain Voltage will be less than VOL and STATUS Pin will go LOW.

Is my understanding correct ?

[Peter BENSCH]

Sorry, I had mistyped point 3, but had already corrected it above.

There is a small leakage current that can flow from the output (drain) to GND, which can be compared to a high-impedance resistor. This "resistor" pulls the output to GND level when there is no load on the output or it has been disconnected and the MOSFET is in OFF state (INPUT = L). For details on open-load detection, see AN4798, section 1.6.

Regards

/Peter