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Associate
February 10, 2025
Solved

Looking for an L9963E C STM32 Library

  • February 10, 2025
  • 2 replies
  • 1850 views

Hi everyone,

I'm currently working on a project where I need to interface an STM32 with the L9963E BMS IC from ST. Before developing my own driver, I wanted to check if anyone has already written a C library for this IC and would be willing to share it or provide some guidance.

If you have experience with the L9963E and have developed a driver, I'd appreciate any insights, code references, or suggestions you can provide.

Thanks in advance!

Best answer by antonio_capone

I’m closing this thread as I’ve decided to develop my own open-source driver, that will be accessible from https://github.com/antoniocapone/l9963-open . For reference, there is also an existing driver that supports the use of the L9963T transceiver (and for now it works only with the transceiver), https://github.com/squadracorsepolito/L9963E_lib.

Special thanks to every people that answered to my question.

2 replies

Andrew Neil
Super User
February 10, 2025
A complex system that works is invariably found to have evolved from a simple system that worked.A complex system designed from scratch never works and cannot be patched up to make it work.
Associate
February 10, 2025

Hi Andrew,

I have already seen this page. The evaluation board's firmware source code is not provided.

Peter BENSCH
Technical Moderator
February 14, 2025

The L9963E is an automotive device whose software is usually only available from your local distributor or STMicroelectronics office.

Hope that helps?

Regards
/Peter

antonio_caponeAuthorBest answer
Associate
February 18, 2025

I’m closing this thread as I’ve decided to develop my own open-source driver, that will be accessible from https://github.com/antoniocapone/l9963-open . For reference, there is also an existing driver that supports the use of the L9963T transceiver (and for now it works only with the transceiver), https://github.com/squadracorsepolito/L9963E_lib.

Special thanks to every people that answered to my question.