The Outputs (U,V,W) of my STEVAL-IPM10F do not get any current.

[IGücl.1]

Hello,

I have an IPM10F and try to switch on the gate, so I can measure a current on the Output U. My Problem is I measure nothing.

I put a constant 3.3 Voltage to the Gate-Pin A-High. On the Output (U) I connect a resistance to override the LOW-Switch. After that I tried to measure with a multimeter. I linked one end to the resistance and the other to the ground, like normal.

Thank you

[Salvo L.]

Please provide the wiring diagram and the resistor value.

Thanks.

[IGücl.1]

The first picture is the wiring diagram of the IGBT and the second from the STEVAL-IPM10F. I used 470k ohm resistors. After my question I tested the output by wiring three resistors 470k into a star connection and link them into the outputs (U,V,W). When I turned it on and put 400V, the oscilloscope showed how the voltage fall down, but with that current this should be impossible, so there is something wrong. Thank you!

[Salvo L.]

Please use the first configuration, I mean the config. used in your first post, if you want to turn-on the High-Side Switch (or the Low-Side).

If you want to test the High Side switch:

1. Connect a Load resistor between U-OUT (or V-OUT, W-OUT if you want to test another output) and GND. The resistor value should be much lower than 470Kohm (ex 470ohm).
2. Connect Oscilloscope to Out-U
3. Apply 15V toVcc
4. Apply 300V to DC Bus Voltage
5. Using a Signal Generator, send a short pulse 0->3.3V (ex. 1ms) to PWM-A-H (to turn on U High Switch). The resistor power dissipation must be taken into account during this test.

If you want to test the Low-Side switch, use the same config as above but this time connect the resistor between U-OUT and P. For this test apply the input signal to the PWM-A-L input.

Hope this helps you.

[IGücl.1]

I tried to test the High-Side switch with your points and it doesn't work. Is there a function in the IGBT, where I have to set the Low-side of high first before the High-side?

Thank you

[IGücl.1]

After a few researches, I found out, that the there is a bootstrap circuit. In that case you can't control the H-Side without first charging the Bootcapacitor.

Thank you and a have a nice day