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JELLY.1
Associate II
May 14, 2024
Solved

Asymmetric Serial Packet Exchange Protocol

  • May 14, 2024
  • 2 replies
  • 1163 views

We have been told Asymmetric Serial Packet Exchange Protocol documentation would be available with the release of MC Workbench V6. We're at V6.3 now. Can you direct me to where I might find said documentation?

The old serial communication class available in MC Workbench 5.4.8 doesn't seem to work with the new Workbench versions.

Here I sit at 5.4.8 wondering, where is the flying car I was promised?

Thank you in advance.

    Best answer by cedric H

    Hello @JELLY.1,

    > Can you direct me to where I might find said documentation?

    Yes sure, 

    From Workbench Tool : About Menu, Documentation->Documentation.

     

    cedricH_0-1715879923375.png

     

    It opens the complete documentation in your default browser.

    From then, you have the User Manual,

    cedricH_1-1715880051334.png

    that contains the Motor Control Protocol Suite section.

    cedricH_2-1715880151277.png

    This documentation is available from MCSDK 6.1.0 released in December 2022.

    Regards

    Cedric

     

     

     

    2 replies

    cedric H
    cedric HBest answer
    Technical Moderator
    May 16, 2024

    Hello @JELLY.1,

    > Can you direct me to where I might find said documentation?

    Yes sure, 

    From Workbench Tool : About Menu, Documentation->Documentation.

     

    cedricH_0-1715879923375.png

     

    It opens the complete documentation in your default browser.

    From then, you have the User Manual,

    cedricH_1-1715880051334.png

    that contains the Motor Control Protocol Suite section.

    cedricH_2-1715880151277.png

    This documentation is available from MCSDK 6.1.0 released in December 2022.

    Regards

    Cedric

     

     

     

    JELLY.1
    JELLY.1Author
    Associate II
    May 20, 2024

    Well I seem to have egg on my face. When all else fails, read the manual!

    Now all I have to do is understand it.

    Thank you Cedric.